How do you find the derivative of ##(cot^(2)x)##?

##-2″cosec”^2 x. cotx##

##f(x) = cot^2x##

##d [f(x)]/dx = 2cot x.(-“cosec”^2x).1##

##= -2″cosec”^2 x. cotx##

first you get the derivative of the indice, then the trig function, lastly the x. it’s easy if you remember it that way 😉