How doyou find the derivative of ##2sinxcosx##?

##2sinxcosx=sin2x##

using the , the derivative is ##2cos2x##

Here is how, ##d/dx(sinx)=cosx## The chain rule for this case is ##d/dx(sinf(x))=f'(x)*cosf(x)##

Thus ##d/dx(sin2x)=2cos2x##