# new drug that is used to treat leukemia, accounting homework help

1. There is a new drug
that is used to treat leukemia. The following data represents the remission
time in weeks for a random sample of 21 patients using the drug.

 10 7 32 23 22 6 16 11 20 19 6 17 35 6 10 34 32 25 13 9 6

Let X be a random variable representing
the remission time in weeks for all patients using the new drug. Assume that
the distribution of x is normal. A previously used drug treatment has a mean
remission time of 12.5 weeks. Does the data indicate that the mean remission
time using the new drug is different from 12.5 week at a level of significance
of 0.01?

State the null hypothesis:

A. µ=12.5

B. µ≠12.5

C. µ<12.5

D. µ>12.5

Answer: Choose an item.

State the alternative hypothesis:

A. µ=12.5

B. µ≠12.5

C. µ<12.5

D. µ>12.5

Answer: Choose an item.

 Let X be a random variable representing the remission time in weeks for all patients using the new drug. Assume that the distribution of x is normal. A previously used drug treatment has a mean remission time of 12.5 weeks. Does the data indicate that the mean remission time using the new drug is different from 12.5 week at a level of significance of 0.01?

State the level of
significance:

A. 0.001

B. 0.01

C. 0.05

D. 0.10

Answer: Choose an item.

 Let X be a random variable representing the remission time in weeks for all patients using the new drug. Assume that the distribution of x is normal. A previously used drug treatment has a mean remission time of 12.5 weeks. Does the data indicate that the mean remission time using the new drug is different from 12.5 week at a level of significance of 0.01?

State the test
statistic:

A. 0.058

B. 0.552

C. 1.058

D. 2.106

Answer: Choose an item.

Perform calculations

Please write down your solutions or
copy and paste your Excel output here:

Then answer the following two
questions:

Critical value:

A. 0.050

B. 1.960

C. 2.086

D. 2.845

Answer: Choose an item.

P-value:

A. p <0.001

B. 0.001 ≤ p <0.01

C. 0.01 ≤ p <0.05

D. 0.05  ≤ p

Answer: Choose an item.

Statistical Conclusion

A. Reject the null
hypothesis

B. Do not reject the null
hypothesis

Answer: Choose an item.

Experimental Conclusion

A. There is sufficient
evidence to conclude that the mean remission time using the new drug is
different from 12.5 week at a level of significance of 0.01.

B. There is no sufficient
evidence to conclude that the mean remission time using the new drug is
different from 12.5 week at a level of significance of 0.01.

Answer: Choose an item.

2. We wish to test the
claim that the mean body mass index (BMI) of men is equal to the mean BMI of
women.  Use the data below to test this claim.

 Men Women 20 29 37 28 46 20 23 28 20 42 23 45 21 19 15 45 20 16 28 32 27 38 20 45 30 41 22 34 27 28 38 21 29 42 20 21 16 30 27 28 42 30 37 43 39 40 39 16 32 44 16 15 21 16 26 20 17 41 39 16

State the Null Hypothesis

A. μ= μ2

B. μ≠ μ2

C. μ> μ2

D. μ< μ2

Where μand μ2 are the mean body mass index
for men and women, respectively.

Answer: Choose an item.

State the alternative hypothesis:

A. μ= μ2

B. μ≠ μ2

C. μ> μ2

D. μ< μ2

Answer: Choose an item.

State the Level of significance

State the level of significance:

A. 0.001

B. 0.01

C. 0.05

D. 0.10

Answer: Choose an item.

State the test statistic (its absolute
value, for example the absolute value of -1.5 is 1.5):

A. 0.058

B. 0.515

C. 1.273

D. 2.108

Answer: Choose an item.

Perform calculations

Please write down your solutions or
copy and paste your Excel output here:

Then answer the following two questions:

Critical value:

A. 0.050

B. 1.960

C. 2.002

D. 2.045

Answer: Choose an item.

P-value:

A. p <0.001

B. 0.001 ≤ p <0.01

C. 0.01  ≤ p <0.05

D. 0.05  ≤ p

Answer: Choose an item.

Statistical Conclusion

A. Reject the null
hypothesis

B. Do not reject the null
hypothesis

Answer: Choose an item.

Experimental Conclusion

There is sufficient evidence to conclude that the
mean body mass index (BMI) of mean is